Question

7(y+3)-2(x+2)=14; 3x+4y=19 solve simultaneously​

Answer 1

Answer:

The given equations are

7(y + 3) - 2(x + 2) = 14 ....(i)

4(y - 2) + 3(x - 3) = 2 ....(ii)

Consider

7(y + 3) - 2(x + 2) = 14

⇒ 7y + 21 - 2x - 4 = 14

⇒ -2x + 7y = -3

⇒ 2x - 7y = 3

⇒ 2x = 7y + 3

⇒ x =

7y+3/2 ....(iii)

Now, consider equation

4(y - 2) + 3(x - 3) = 2

⇒ 4y - 8 + 3x - 9 = 2

⇒ 3x + 4y = 19

⇒

3(7y+3/2)+4y = 19 ....[From (iii)]

⇒

21y+9+8y/2 = 19

⇒ 29y + 9 = 38

⇒ 29y = 29

⇒ y = 1

Substituting value of y in eqn. (iii), we get

x =

7(1)+3/2

10/2

= 5

Thus, the solution set is (5, 1).

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Answer:

The given equations are

7(y + 3) - 2(x + 2) = 14 ....(i)

4(y - 2) + 3(x - 3) = 2 ....(ii)

Consider

7(y + 3) - 2(x + 2) = 14

⇒ 7y + 21 - 2x - 4 = 14

⇒ -2x + 7y = -3

⇒ 2x - 7y = 3

⇒ 2x = 7y + 3

⇒ x =

7y+3/2 ....(iii)

Now, consider equation

4(y - 2) + 3(x - 3) = 2

⇒ 4y - 8 + 3x - 9 = 2

⇒ 3x + 4y = 19

⇒

3(7y+3/2)+4y = 19 ....[From (iii)]

⇒

21y+9+8y/2 = 19

⇒ 29y + 9 = 38

⇒ 29y = 29

⇒ y = 1

Substituting value of y in eqn. (iii), we get

x =

7(1)+3/2

10/2

= 5

Thus, the solution set is (5, 1).

Step-by-step explanation:

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