7(y+3) - 2 (x+2) = 14, 4(y - 2 ) +3(x - 3) = 2.
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Answer:
7(y+3)-2(x+2)=14
=>7y+21-2x-4=14
=>7y+17-2x=14
=>7y-2x=14-17
=>7y-2x=-3 ------1st equation
4(y-2)+3(x-3)=2
=>4y-8+3x-9=2
=>4y+3x-17=2
=>4y+3x=2+17
=>4y+3x=19 ------2nd equation
3[7y-2x=-3]
2[4y+3x=19]
21y-6x=-9 -------3rd equation
8y+6x=38 -------4th equation
by elimination
adding eqation 3 and 4
we get 29y=29
=>y=1
put 'y' is equal to 1 in equation 3
7-2x=-3
-2x=-10
=>x=5
therefore
y=1,x=5
Answered by
1
x+y-8/2=x+2y-14/3=3x+y-12/11
just ingnore my handwriting
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