7(y+3)-2(x+2)=14
4(y-2)+3(x-3)=2
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Answered by
17
7y+21-2x-4=14
7y-2x=14+4-21
7y-2x=18-21
7y-2x=-3--------(1)*3
4y-8+3x-9=2
4y+3x=2+9+8
4y+3x=19-------(2)*2
On adding both equation (1) & (2) we get:-
21y-6x=-9
8y+6y=38
--------------------
29y=29
y= 1
Therefore putting the value of y=1 in equation (2) we get :-
4y+3x=19
4+3x= 19
3x= 19-4
3x= 15
X= 5
Hence, X= 5 & y=1
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Answered by
5
1)7y+21-2x-4=14
=7y-2x=14-17
=7y-2x=-3
let let y be 1 and x be 5
7(1)-2(5)=-3
7-10
=-3=-3
lhs=rhs
2)4y-8+3x-9=2
4y+3x=2+17
4y+3x=19
lhs not equal to rhs
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