Question

7(y+3)-2(x+2)=14 , 4(y-2)+3(x-3)=2 by substitution methods class 10 maths​

Answer 1

Answer:

$\mathrm{7\left(y+3\right)-2\left(x+2\right)=14,\:4\left(y-2\right)+3\left(x-3\right)=2\quad :\quad y=1,\:x=5}$

Step-by-step explanation:

$\begin{bmatrix}\mathrm{7\left(y+3\right)-2\left(x+2\right)=14} \\ \mathrm{4\left(y-2\right)+3\left(x-3\right)=2 } \end{bmatrix}$

$\mathrm{Substitute\:y=\frac{2x+18}{7}-3}$

$\begin{bmatrix}\mathrm{4\left(\frac{2x+18}{7}-3-2\right)+3\left(x-3\right)=2} \end{bmatrix}$

$\begin{bmatrix}\frac{29x+72}{7}-29=2\end{bmatrix}$

$\mathrm{For\:y=\frac{2x+18}{7}-3}$

$\mathrm{Substitute\:x=5}$

$y=\frac{2\cdot \:5+18}{7}-3$

$y=1$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$y=1,\:x=5$