Question

7(y + 3) - 2( x + 2) = 14
4(y -2) + 3(x -3) =2
eliminate method​

Answer 1

Answer:

7(y+3) - 2(x+2) =14

7y + 21 - 2x - 4 = 14

7y - 2x + 17 = 14

7y - 2x + 3 = 0 (1)

4(y-2) + 3(x-3) = 2

4y - 8 + 3x - 9 = 2

4y + 3x - 17 = 2

4y + 3x - 19 = 0 (2)

Multiplying (1) by 3,

3(7y - 2x + 3) = 0

21y - 6x + 9 = 0 (3)

Multiplying (2) by 2

2(4y + 3x - 19) = 0

8y + 6x - 38 = 0 (4)

Adding (3) and (4),

21y - 6x + 9 + 8y + 6x - 38 = 0

21y + 8y - 29 = 0 (cancelling

+6x

and -6x)

29y - 29 = 0

29(y - 1) = 0

y - 1 = 0

y = 1

substituting value of y in (1),

7(1) - 2x + 3 = 0

7 + 3 - 2x = 0

10 - 2x = 0

2(5 - x) = 0

5 - x = 0

x = 5

Thus, y = 1, x = 5