Question

7(y+3)-2(x+2)=14 & 4(y-2)+3(x-3)=2 solve it by elemination method ​

Answer 1

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Answer 2

7(y+3)-2(x+2)=14.........eq (i)

4(y-2)+3(x-3)=2........eq (ii)

On solving eq (i) and (ii)

7y+21-(2x+4)=14

4y-8+(3x-9)=2

7y+21-2x-4=14

4y-8+3x-9=2

7y-2x+17=14

4y+3x-17=2

7y-2x=14-17

4y+3x=2+17

7y-2x=-3 ×3

4y+3x=19 ×2

21y-6x=-9

8y+6x=38

On adding eq (i) and (ii)

29y=29

Y=29/29

Y=1

Put value of y in eq (i)

7(1)-2x=-3

7-2x=-3

7+3=2x

10=2x

X=10/2

X=5

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