Math, asked by tanishq15271, 9 months ago

7 years ago, the difference between the ages of A and B was 14 years. After 7 years, the ratio of ages will be 3:4, what is the present age of A?

Answers

Answered by ShelleyBurnwal
0

Answer:

35years

Step-by-step explanation:

Let the ages of A and B after 7years be 3x and 4x.

Their present ages are:- (3x-7)years and (4x-7)years.

7years ago,

Age of A = 3x-7-7 = (3x-14)years

Age of B = 4x-7-7 = (4x-14)years

A/Q,

(4x-14)-(3x-14) = 14

4x-14-3x+14 = 14

x = 14

Now, present age of A = 3x-7 = 3×14-7 = 42-7 =35years

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