7 years ago, the difference between the ages of A and B was 14 years. After 7 years, the ratio of ages will be 3:4, what is the present age of A?
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Answer:
35years
Step-by-step explanation:
Let the ages of A and B after 7years be 3x and 4x.
Their present ages are:- (3x-7)years and (4x-7)years.
7years ago,
Age of A = 3x-7-7 = (3x-14)years
Age of B = 4x-7-7 = (4x-14)years
A/Q,
(4x-14)-(3x-14) = 14
4x-14-3x+14 = 14
x = 14
Now, present age of A = 3x-7 = 3×14-7 = 42-7 =35years
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