Question

70−{−8×(10−27÷3)− (4−6+3)}

Answer 1

Answer:

70−{−8×(10−27÷3)− (4−6+3)} = 79

Step-by-step explanation:

The BODMAS rule is an acronym that is used to recall the order of operations to apply while solving mathematical problems. B stands for brackets, O is for order of powers or roots, D stands for division, and M stands for multiplication. A stands for addition, and S stands for subtraction.

70−{−8×(10−27÷3)− (4−6+3)}

=70−{−8×(10−9)− (4−6+3)}

=70−{−8× 1 − (4−6+3)}

=70−{−8× 1 − (4−3)}

=70−{−8× 1 − 1}

=70−{−8− 1}

= 70 - (-9)

= 70 + 9

= 70

Answer 2

Given: The equation is$70-[-8\times(10-27\div3)- (4-6+3)]$

We have to solve the above equation.

By using the Bodmas rule, we are solving the above equation.

As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

The equation is$70-[-8\times(10-27\div3)- (4-6+3)]$

$= 70-[-8\times(10-27/3)-(4-6+3)]\\= 70-[-8\times(10-9)-(4-6+3)]\\= 70-[-8\times(1)-(4-6+3)]\\= 70-[-8\times1-(4-6+3)]\\= 70-[-8\times1-(-2+3)]\\= 70-[-8\times1-(1)]\\= 70-[-8\times1-1]\\= 70-[-8-1]\\= 70-[-9]\\= 70--9\\= 70+9\\= 79$

Hence, the solution of the above equation is$79$.