Question

70
A
t(s)
ol
10.7
ilustration 22.
Velocity-time graph of a particle moving in a straight line is shown. Plot the corresponding displacement-time
graph of the particle
Solution
V(m/s)
Displacement - area under velocity-time graph.
20
Hence, SA
2x2
1
x 2 x 10 = 10 m
2
A
10
B
SAB
2 x 10 = 20 m
10+20 - 30 m
SOAB
6
8
10+20
Soc
30 m
- 2x
2
SOASO
30+30 - 60 m
30
and
(2 x 20) - 20m
SC
SonCo - 60+ 20 - 80 m
celerated hence displacement-time graph is a parabola Between 2 to​

Answer 1

Answer:

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