Question

70 cm long wire is cut into 2 parts such that first part is equal to two fifth of the second part, then the length of smaller part is

Answer 1

let the second part = x

first part = 2/5 of x

x + 2x/5 = 70

7x/5 = 70

x = 50

so one part is 50

another part = 70 - 50 = 20

the length of the smaller part is 20

Answer 2

$\textbf{Let \: the \: parts \: cutted \: from \: long \: w ire \: are \: \: x \: cm \: a nd \: \: ( 70 - x ) cm} \:$



$\mathbf{As \: discussed \: in \: the \: question, } \\ \\ \mathbf{ First \: part = two - fifth \: of \: second \: part } \\ \\ \\ => x = \frac{2}{5} (70 - x) \\ \\ => 5x = 140 - 2x \\ \\ = >5x + 2x = 140 \\ \\ = > 7x = 140 \\ \\ \\ = > x = \frac{140}{7} \\ \\ \\ x = 20$





Parts are :

x = 20
70 - x = 70 - 20 = 50



$\bold{ Parts : 20 \: and \: 50}$