Question

70 degree complement
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Answer 1

Answer:

Step-by-step explanation:

$\lim_{n \to \infty} a_n x^{2} \sqrt{x} \sqrt[n]{x} \geq \leq x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} \beta \ \lim_{n \to \infty} a_n \neq \geq x^{2} \int\limits^a_b {x} \, dx \sqrt{x} \left \{ {{y=2} \atop {x=2}} \right. \\ \leq alpha \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]$

Answer 2

Answer:

explanation

Step-by-step explanation:

complement is 70 is 90 -- 70 = 20

hope you understand the brainly