Math, asked by Divyankasc, 1 year ago

70 Points! Please help! I didn't quite get the question as well. Please explain it. I would be really really really grateful! :)

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Divyankasc: Ahhh...I forgot to put 70 points! Sorry ppl :(

Divyankasc: It's just of 10 points

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Answered by FlameFires

I think this should be right..Explanation : The question has given a situation of x Co ordinates of a particle varying with time and it turns out to be a motion of uniform acceleration. Initially the particle is at x=1 and if we check, the velocity takes positive values. They are asking till what time the particle moves in positive x direction, I. e., till what time is the velocity towards positive x. So what they re actually asking is, when will the velocity of the particles become zero for the first time. (which is consequently also the time when it reverse direction and starts moving alone negative x.

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Divyankasc: How do we know it changes at t = 2 ?

Divyankasc: I mean velocity changes sign at* ^^"

FlameFires: Because at that point velocity becomes zero. If you write increasing values of t after that, velocity assumes negative values.

Divyankasc: Oh okay, I understood it now!

Divyankasc: ∞∞∞∞∞∞ Thanks !

FlameFires: It's more of an analysis of the function itself. If you plot the velocity against time in a graph you'll see. Moreover, since velocity becomes zero at that time, it can either become positive again or negative. however, it was initially positive too. if it will continue to be positive, it must be quadratic function of t. However it is a linear (and without modulus operator), hence it changes sign.

Divyankasc: God, I see, Whooo T_T xD Thanks for helping me so many times

FlameFires: Welcome. Any more?

Divyankasc: I don't have any more for now. If I have any, I'll post all the doubts I have any altogether later. I'm highly grateful. Really.

Divyankasc: Wait, one,

Answered by kokan6515

here is the answer in pic.......

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