700 + 10b + c = 800 – 45; c = ______ b = ______, ...
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By solving the equation in the last we get
10b + c = 55
Therefore , there are many ordered pairs of b and c.
(1) b = c = 5
(2) b = 6 , c = -5
(3) b = 4 , c = 15
and so on .................................................
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