700
EXERCISE 2.2
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2 Jouger
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3.
1. If you subtract from a number and multiply the result by
the number?
2. The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than
twice its breadth. What are the length and the breadth of the pool?
3. The base of an isosceles triangle is cm. The perimeter of the triangle is
What is the length of either of the remaining equal sides?
4. Sum of two numbers is 95. If one exceeds the other by 15, find the numbers
5. Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?
6. Three consecutive integers add up to 51. What are these integers?
of the consecutive multiples of's is 888. Find the multiples
Answers
Answer:
Let the no. Be X.
Subtract 1/2 from X, which is (x-1/2)——(I)
Multiply (I) by 2, to get 1/8
(X-1/2)×2=1/8
(X-1/2)=(1/8)×1/2
(X-1/2)=1/16
X=1/16+1/2
X=(1+8)/16
X=9/16.
Check:
X-1/2 × 2
=(9/16–1/2)×2
=(9–8)/16×2
(1/16)×2
=1/8
2:Let the breadth of rectangular swimming pool be x metres.
Then, its length =(2x+2) metres.
We know that the Perimeter of a rectangle =2(Length+Breadth)
=2(2x+2+x)=6x+4
According to the given condition, we have
6x+4=154
⇒6x=154−4 ..[By transposing 4 to RHS]
⇒6x=150
⇒6x=6150 ...[Dividing both sides by 6]
⇒x=25
Thus, breadth =25 m and length =25×2+2=52 m
So, base = 4/3cm
Perimeter = 4*2/15 = 8/15cm
So let the equal sides be x cm
So,
x+x+4/3 = 8/15cm
2x = 8/15 - 4/3
2x = 8-20/15 (By taking the lcm as 15)
2x = -12/15
x = -12/30 (By multiplying 1/2 on both the sides)
x = -2/5
Let the first number be x
second number be (x+15) // one exceed other by 15 //
sum of the number is given by x+(x+15) = 95
x+x+15=95
2x+15 = 95
2x =95-15
2x = 80
x=80/2
x =40
first number x=40, second number x+15 = 40+15= 55
The numbers are 40 and 55.
. Let smallest unknown no. be x
Than second no. be x+1
And third no. be x+2
Given-
x+x+1+x+2=51
3x+3=51
3x=51-3
3x=48
x=48/3
x=16
So, three consecutive numbers are 16, 17 and 18