.700kg of mortar consisits of 53% sand, 129 kg of cement and the rest lime.
What percent of the lime is there in mortar?
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Cement =129kg
Sand =53/100×700 (53%=53/100)
lime =Let it be'x'=x
129+53/100×700+x=700
129+53×7+x =700
129+371+x =700
500+x =700
x =700-500
x =200kg
sand =53/100×700
=53×7
=371kg
cement=129kg
lime =200kg
Sand =53/100×700 (53%=53/100)
lime =Let it be'x'=x
129+53/100×700+x=700
129+53×7+x =700
129+371+x =700
500+x =700
x =700-500
x =200kg
sand =53/100×700
=53×7
=371kg
cement=129kg
lime =200kg
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65.22 percent of lime
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