Question

70ml of carbon monoxide (CO) is reacted with 30ml of oxygen (O2). What volume in mL of carbon dioxide (CO2) is formed?
2CO + O2 --> 2CO2

Answer 1

Explanation:

According to law of conservation of mass ,"mass can neither be created nor destroyed in a chemical reaction ".

so ,

when 70 ml of carbon monoxide (CO) is reacted with 30 ml of oxygen (O2) the volume of ml formed of carbon dioxide is 100ml with simple addition.

reaction:-

2CO(70Ml)+O2(30Ml) -------------> 2CO2(100Ml)

(reactants) ( Products)

Note:Never forget to balance the reaction.

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Answer 2

Answer:

The correct answer is 40 ml.

According to law of conservation of mass ,"mass can neither be created nor destroyed in a chemical reaction ".

so ,when 70 ml of carbon monoxide (CO) is reacted with 30 ml of oxygen (O2) the volume of ml formed of carbon dioxide is 100ml with simple addition.reaction:-

2CO(70Ml)+O2(30Ml) -------------> 2CO2(100Ml)(reactants) ( Products)

Explanation:

2CO(g)+O2​(g)→2CO2​(g)

2 volumeS of CO gas reacts with 1 volume of O2​ gas

70 ml of CO gas reacts with 35 ml of O2​ gas

But we have 30 ml of O2​ gas

So the limiting reagent is CO gas

70 ml of CO gas would have consumed 35 ml of O2​ gas

Remaining volume of CO gas = 0 ml

Remaining volume of O2​ gas = 70-30=40 ml

Now2 volumes of CO gas gives with 2 volumes of CO2​ gas

40 ml of CO gas gives with 20 ml of CO2​ gas

Total volume of the mixture of gases presents after the reaction =0+20+20=40ml. 
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