Question

71. As shown in figure, a particle of mass m is performing vertical circular motion. The velocity of the particle is increased, then at which point will the string break?​

Answer 1

Answer:

B

Explanation:

because at point B the downward force of gravity is directly opposing the tension force and due to the conservation of energy the velocity of the object will be highest at the lowest point which also accounts in the favour of the breaking of the string. At the position, A and C mg acts downwards perpendicular to T and at the point D, mg acts downwards with the T which also acts downwards to it would resist the breaking of the string.