71 g of chLORINE COMBINES WITH A METAL GIVING 111 g OF ITS CHLORIDE THE CHLORIDE IS ISOMORPHOUS WITH MgCL2.6H2O THE ATOMIC MASS OF THE METAL IS....
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Hello there,
● Answer -
Atomic mass of metal would be = 20 g/mol
● Explaination -
Let x be the mass of metal reacted.
Reaction : M + Cl2 --> MCl2
Initially : x 71 0
Equilibrium : 0 0 x+71
But we know,
Products formed = 71 + x = 111
x = 111 - 71 = 40 g
Moles of Cl2 = 71/35.5 = 2
Atomic mass of metal would be -
M = 40/2 = 20 g/mol
Therefore, atomic mass of element is 20 g/mol.
Hope this helps you...
● Answer -
Atomic mass of metal would be = 20 g/mol
● Explaination -
Let x be the mass of metal reacted.
Reaction : M + Cl2 --> MCl2
Initially : x 71 0
Equilibrium : 0 0 x+71
But we know,
Products formed = 71 + x = 111
x = 111 - 71 = 40 g
Moles of Cl2 = 71/35.5 = 2
Atomic mass of metal would be -
M = 40/2 = 20 g/mol
Therefore, atomic mass of element is 20 g/mol.
Hope this helps you...
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