71) Isopropyl bromide reacts with alcoholic KOH to give :
a) Propene
b) Isopropyl alcohol
c) Propane
d) n-Propyl alcohol
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This leads to the production of propene molecule. When the above compound is treated with alcoholic KOH, it results in the dehydrohalogenation of compound and it results in the formation of propene. hydrogen atom is released along with halogen to form hydrogen halide.
Explanation:
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