Math, asked by chaturvedikanchan343, 10 months ago

71
sin A
sec A + tan A-1
cos A
cosec A + cot A-1
=
1​

Answers

Answered by sandy1816
4

Step-by-step explanation:

sinA/secA+tanA-1 + cosA/cosecA+cotA-1

=sinAcosA/1+sinA-cosA + sinAcosA/1+cosA-sinA

=sinAcosA[1/1+sinA-cosA + 1/1-(sinA-cosA)]

=sinAcosA[1-sinA+cosA+1+sinA-cosA/1-(sinA-cosA)²]

=sinAcosA[2/1-(1-2sinAcosA)]

=sinAcosA[2/2sinAcosA]

=1

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