Question

71. The circular ends of a bucket are of radii 35 cm and 14 cm and the height
of the bucket is 40 cm. Its volume is
(a) 60060 cm (b) 80080 cm (c) 70040 cm (d) 80160 cm
also tell formula​

Answer 1

Answer:Let R and r be the radii of the top and base of the bucket, respectively, and let h be its height. Hence, the volume of the bucket is 80080 cm3.

Step-by-step explanation:

Answer 2

Answer:

option b) 80080 cm²

➠R= 35cm

➠r = 14cm

➠h = 40 cm

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The bucket is in the shape of a frustum of a cone.

Volume of a frustum of a cone = ⅓πh (R² + r² + Rr)

where h is the height and R and r are the radii of the lower and upper ends of a frustum

of a cone. Hence, volume of the frustum of the cone =

$\frac{1}{3} \times \frac{22}{7} \times 40(35 {}^{2} + {14}^{2} + 35 \times 14) \\ = \frac{1}{3} \times \frac{22}{7} \times 40(1911) \\ = \frac{1681680}{21} \\ = 80080cm ^{2}$