71x+37y=253 37x+71y=287
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Answered by
290
71x+37y=253 ...(i)
37x+71y=287 ...(ii)
add (i) and (ii) to get
108(x+y)=540
= x+y=5 ....(iii)
substract (ii) from (i) to get
34(x-y)=-34
=x-y=-1 ...(iv)
add (iii) and (iv)
x+y+x-y=5+(-1)
=2x=4
=x=2
putting the value of x in(iii) we get
2+y=5
y=3
hence x=2 and y=3
37x+71y=287 ...(ii)
add (i) and (ii) to get
108(x+y)=540
= x+y=5 ....(iii)
substract (ii) from (i) to get
34(x-y)=-34
=x-y=-1 ...(iv)
add (iii) and (iv)
x+y+x-y=5+(-1)
=2x=4
=x=2
putting the value of x in(iii) we get
2+y=5
y=3
hence x=2 and y=3
Answered by
58
Answer:
x=2 ;y=3
71x+37y=253 --- (1)
37x+71y=287------(2)
By substitution Method
step 1:-We pick either of the equation and write one variable in terms of other
let us consider equation 1
71x+37y=253
71x=253-37y
x=253-37y/71--(3)
Step 2:- substituting this value of x from equation 3 in equation 2
37{253-37y/71}+71y =287
9361-1369y/71+71y =287
1(9361 -1369y)+71(71y)/71=287
9361 -1369y+5041y=287(71)
9361+ 3672y=20377
3672y = 20377 - 9361
y=11016/3672
y=3
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