Question

(√72-√18)+√12 solve​

Answer 1

Answer:

(√72-√18)÷√12

(6√2-3√2)÷2√3

3√2÷2√3

(√3×√3×√2)÷√2×√2×√3 ( :- 3=√3×√3 ; 2=√2×√2 )

now ,

√3 and √2 will be cancelled in both numerator and denominator .

√3÷√2 =√(3÷2) .

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Answer 2

Answer:

the answer is 3 root 2

Step-by-step explanation:

Explanation:

The square root of

72

minus square root of

18

can be expressed as

√

72

−

√

18

Now,

√

72

=

√

3

2

⋅

2

2

⋅

2

=

6

√

2

√

18

=

√

3

2

⋅

2

=

3

√

2

6

√

2

−

3

√

2

=

3

√

2