Math, asked by pawan375, 1 year ago

72 : 18 :: 56 : ?
(a) 24
(c) 20
(b) 22
(d) 16​

Answers

Answered by maglangitjessie7
0

Answer:

Solution 1:

72/18 = 56/N

72N = 56(18)

72N = 1008

divide both sides by 72 then eliminate 72 on left side

ans: 14

Solution 2:

18

72 = 4 * 18

----------------

56 = 4 * 14

therefore N is 14

or

72/18 = 56/N

convert to the lowest term 72/18 = 4

4 = 56/N

cross multiply

4N = 56

4N/4 = 56/4

N = 14

Step-by-step explanation:

Answered by pulakmath007
0

72 : 18 :: 56 : 22

Given :

72 : 18 :: 56 : ?

To find :

The number in "?" is

(a) 24

(b) 22

(c) 20

(d) 16

Solution :

Step 1 of 2 :

Find the pattern

Here it is given that 72 : 18 :: 56 : ?

Now ,

72 : [(7 + 2) × 2]

= 72 : (9 × 2)

= 72 : 18

Thus the pattern is

For a two digit number ab

ab : [(a + b) × 2]

Step 2 of 2 :

Find the number in "?"

For the number 56 we get

56 : [(5 + 6) × 2]

= 56 : (11 × 2)

= 56 : 22

Thus we have , 72 : 18 :: 56 : 22

Hence the correct option is (b) 22

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