72 and 105 using euclid division algorithm
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11
105=72*1+33
72=33*2+6
33=6*5+3
6=3*2+0
hcf =3
72=33*2+6
33=6*5+3
6=3*2+0
hcf =3
Answered by
8
Consider the greater number as 'a ' & smaller number as 'b' and then apply euclid's division algorithm to get the required HCF
Euclid's Division algorithm
a= bq+r
Here, 105>72
Let a= 105, b= 72
By using euclid's division Lemma,
105= 72×1+33
Here Remainder = 33≠0
Again on applying euclid's division Lemma
72= 33×2+ 6
Here, Remainder = 6≠0
Again on applying euclid's division Lemma
33= 6×5+3
Here, Remainder= 3≠0
Again on applying euclid's division Lemma
6= 3×2+ 0
Here , Remainder = 0 & divisor is 3
Hence, the HCF of 72 & 105 is 3
==================================================================
Hope this will help you...
Euclid's Division algorithm
a= bq+r
Here, 105>72
Let a= 105, b= 72
By using euclid's division Lemma,
105= 72×1+33
Here Remainder = 33≠0
Again on applying euclid's division Lemma
72= 33×2+ 6
Here, Remainder = 6≠0
Again on applying euclid's division Lemma
33= 6×5+3
Here, Remainder= 3≠0
Again on applying euclid's division Lemma
6= 3×2+ 0
Here , Remainder = 0 & divisor is 3
Hence, the HCF of 72 & 105 is 3
==================================================================
Hope this will help you...
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