Physics, asked by Nishantabhi, 2 months ago

72. For one mole of a van der Waals' gas, the
compressibility factor Z =
pV
at a fixed volume
RT
will certainly decrease, if
[Given : "4” and “G” are standard parameters for
van der Waals' gas]
(a) “b" increases and "a” decreases at constant
temperature
(b) “b” decreases and “a”'increases at constant
temperature
(c) temperature increases at constant "a" and "B" values
(d) “b” increases at constant "a" and temperature.​

Answers

Answered by subhsamavartj
1

Answer:

More the value of a/b more is the liquefaction and higher is the compressibility  

so, as the compressibility increases the value of Z decreases and as the value of b decreases a increases at constant temperature and the compressibility factor Z decreases.

Hence option B is correct.

Explanation:

Hope it helps


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