Chemistry, asked by utharaudayakumar, 1 year ago

.72 g of a solid fuel containing 80% carbon when burnt in a bomb calorimeter increased temperature of water from 27.3oc to 29.1oc if calorimeter contain 250gm of water and its water equivalent is 150gm calculate the HCV of saple

Answers

Answered by babajipawar0098
0

Answer:

Answer is hcv=1000kcal/kg(or)4200kj/kg

Answered by Anonymous
1

Given:

  • Weight of solid fuel = 0.72 g
  • Weight of water = 250 g
  • Water equivalent = 150 g
  • Temperature 1 = 27.3° C
  • Temperature 2 = 29.1° C

To Find:

  • The HCV of the sample.

Solution:

The formula to find HCV is given by,

HCV = \frac{(W+w)(t_2-t_1)}{m}  → {equation 1}

where "W" is the weight of water, "w" is water equivalent water, "m" is the weight of solid fuel, "t_2 and t_1" temperatures.

Substitute the values from the given data in equation 1. we get,

⇒ HCV = \frac{(250+150)(29.1-27.3)}{0.72} = \frac{(400)(1.8)}{0.72}

In the above equation, we solved the terms in brackets in the numerator and then multiplied them.

⇒ HCV = 720/0.72 { dividing the terms}

⇒ HCV = 1000 kcal/Kg

∴ The value of HCV = 1000 kcal/Kg.

Similar questions