Question

72 k is a perfect cube , find the value of k​

Answer 1

Answer:

Step-by-step explanation:

$let\;the\;cube\;be\;x^3=72k\\\\72=2*2*2*3*3\\\\72=2^3*3^2\\\\for \;72k \;to\; be \;a\; cube\; k \;must \;be\; equal \;to\; 3\\\\72k=6^3$

Therefore k = 3

Hope it Helps