72. Out of 60 students 25 failed in paper (1), 24 in paper (2), 32 in paper),
alone, 6 in paper (2) alone, 5 in papers (2) and (3) and 3 in papers (1) and (2)
many failed in all the three papers.
(a) 10
(b) 60
(c) 50
(d) None
Answers
Answered by
14
Answer:
total students -60
no. of students failed in
paper 1 - 25
paper 2 - 24
Answered by
16
Answer: its option a
Step-by-step explanation:since it is logical
n(a) = 25 , n (b)= 24 and similarly c = 32 .
The logic behind the sum is in question it is given as a^b = 3 by drawing venn diagram it will clear understand since it is 13. Similarly the value of a^c = 23 , b^c= 15.
After taking the value
We have to prove total is 60 .
N(aubuc)= n(a)+n(b)+n(c)-n(a^b)-n(b^c)-n(a^c)+n(a^b^c)
=25+24+32-13-15-23+10
=60.
IF NO OF STUDENT FAILED THREE WILL BE 10.HENCE DRAW SAME VENN DIAGRAM TAKING ALL THREE STUDENTS PASSED IT WILL RESULT SAME AS 10.
OR
TAKING ONE BY ONE OPTION SUBSTITUTE IN PLACE OF A^B^C .TO GET THE ANSWER AS TOTAL AS 60.
Similar questions