Chemistry, asked by karan879433, 1 year ago

72. The number of bonding electron pairs in N2, on the
basis of molecular orbital theory is​

Answers

Answered by 007theabhishek
22

Answer:

5 pairs

Explanation:

bonding electron pairs are sigma 1s2, sigma 2s2, π2px2, π2py2 and sigma 2pz2

Answered by kobenhavn
8

Thus there are 5 boding electron pairs on the  basis of molecular orbital theory.

Explanation:

According to the molecular orbital theory, the general molecular orbital configuration of boron and carbon will be,

(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),[(\pi_{2p_x})=(\pi_{2p_y})],(\sigma_{2p_z}),[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)

As there are 14 electrons present in nitrogen. The molecular orbital configuration of molecule will be:

(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,[(\pi_{2p_x})^2=(\pi_{2p_y})^2],(\sigma_{2p_z})^2,[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0Thus there are 5 boding electron pairs and 2 non bonding electron pairs.

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