Question

720 ml of a methane diffused through a porus membrane in 30 min. under identical conditions 240 ml of gas ‘X’ diffused in 20 min. Calculate the molecular weight of ‘X’ ​

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

Rate of diffusion, R∝

M

1

∝

t

1

⇒t∝

M

t

1

/t

2

=

M

x

/M

2

M

x

/M

2

=20/10

M

2

= Molar mass of methane = 16

M

x

/16

=20/10

M

x

/16

=2

M

x

=4×2

M

x

= 8

M

x

= 64

Molar mass of x=64 g/mol