Question

720cc of a methane diffused through a
porous membrane in 30min. Under identical
conditions 240cc of gas 'X' diffused in 20min.
Calculate the molecular weight of 'X'.​

Answer 1

Answer:

Explanation:

Rate of methane gas =720cc/30 min=24 cc/min

Similarly rate of unknown gas=240cc/20min=12 cc/min

We know that r is inversely proportional to M^1/2

And r1/r2=$\sqrt{M1/M2}$

GMW of methane=16 let GMW of unknown gas=x

Implies 24/12=$\sqrt{16/x}$

=== 2=$\sqrt{16/x}$

Squaring on both sides

=== 4=16/x

== x=16/4

=== 4 gms

Answer 2

Answer:

I can't understand your question