Question

(729/4096)^-1/3


please solve​

Answer 1

$\boxed{\boxed{\huge{\bf{Hello}}}}$

$\boxed{\boxed{\huge{\bf{Answer = {\frac{16}{9}}}}}}$

This question is totally based on the concept of exponents.

$\boxed{\boxed{\huge{\bf{Step By Step Explaination}}}}$

${\huge{\bf\frac{729}{4096}^\frac{-1}{3}}}$

=${\huge{\bf\frac{4096}{729}^\frac{1}{3}}}$

This fraction is in cube root

Solving the cuberoot

${\huge{\bf\frac{16^3}{9^3}}}$

we will get,

${\huge{\bf\frac{16}{9}}}$

$\boxed{\boxed{\huge{\bf{Extra Information}}}}$

The fraction was in an exponent form which means it implies root as per given in rules of exponents.

And when we reciprocal the fraction then the sign of power changes if it is negative then it become positive and if positive then it become negative.

Answer 2

(4096/729)^1/3



(16/9)^3•1/3




(16/9)^1





(16/9)