Question

7290 = x (1-[10/100])^3

Answer 1

Answer:

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Step-by-step explanation:

Let the cost of the scooter before 3 years was x.

Given that amount = 7290 rupees, r = 10%, n = 3 years.

We know that A = P(1 - r/100)^n

                        7290 = x(1 - 10/100)^3

                       7290 = x(9/10)^3

                       7290 = x * (729/1000)

                       7290 = 729x/1000

                       7290 * 1000 = 729x

                       7290000 = 729x

                       7290000/729 = x

                       10000 = x.

Therefore the value of the scooter before 3 years ago = 10000 rupees.

Answer 2

Answer:

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