Question

729a^3+64b^3
factorise

Answer 1

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$729a ^{3} + 64b ^{3} \\ \\ we \: apply \: this \: identity \: here \: \\ \\ a ^{3} + b ^{3} = (a + b)(a ^{2} - ab + b ^{2} ) \\ \\ = (9a) ^{3} + (4b ^{3} ) \\ \\ = (9a + 4b)((9a) ^{2} - 9a \times 4b + (4b) ^{2} ) \\ \\ = (9a + 4b)(81a ^{2} - 36ab + 16b ^{2} )$




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