Question

72a^3b^4÷(-8a^2b^2)
plss answer with step by step explanation very urgent do not post irrelevant answers if u i will report ​

Answer 1

Answer:

.

Find the sum of first 16 terms of an Arithmetic Progression whose

4th and 9th terms are - 15 and - 30 respectively.

Answer 2

Step-by-step explanation:

Simplify ———————————

23a2b4

Dividing exponential expressions :

3.1 a3 divided by a2 = a(3 - 2) = a1 = a

Dividing exponential expressions :

3.2 b3 divided by b4 = b(3 - 4) = b(-1) = 1/b1 = 1/b

Canceling Out:

3.3 Canceling out 23 as it appears on both sides of the fraction line

Final result :

9a

——

b