Math, asked by jeyaasha490, 1 year ago

73. A person boarded an express train
on 30th August, 2015 at
Ahmedabad for Trivandrum. The
train departed from Ahmedabad at
13.30 h and reached Trivandrum at
7.30 h on 1st September, 2015. If
the distance between Ahmedabad
and Trivandrum is 2268 km, the
average speed of the train between
the two stations was
[CTET Sept 2015]​

Answers

Answered by tan1214
2

total time taken = 18hrs.

distance travelled = 2268km.

therefore, avr. speed= distance÷time

= 2268÷18

=126km/hr

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