Question

73. The distance between two consecutive threads on the
screw of a screw gauge is 0.5 mm. The number of
divisions on the circular scale is 100. A wire is placed
between the studs of the screw gauge. Find the diam-
eter of the wire if the pitch scale shows 14th division
and 40th circular division coincides with the base line.
The given apparatus was detected to have negative zero
error. The 90th division on the circular scale coincides
with reference line, when the studs are in contact.
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Answer 1

Answer:

14.25 mm is the diameter of the wire.

Explanation:

Pitch = 0.5 mm

No. of Circular Scale Divisions = 100

Least Count = Pitch/No. of Circular Scale Divisions

= [0.5/100] mm

= 0.005 mm

Main Scale Reading = 14 mm

Circular Scale Reading = 40 mm

= [40*0.005] mm

= 0.2 mm

= Observed Reading without Zero Error = [14+0.2] mm

= 14.2 mm

Negative Zero Error = - [100-90] * 0.005

= [(-10) * 0.005] mm

= -0.05 mm

Total Reading = Observed Reading - Zero Error (with sign)

= [14.2 - (-0.05)] mm

= [14.2 + 0.05] mm

= 14.25 mm

Hope this helps.