Question

73g of conc.HCL was diluted by adding 144g of water.How many gram atom of hydrogen are present in the dilute acid?Please solve it fast

Answer 1

Dear Student,

◆ Answer -

Moles of hydrogen = 18 gram-atoms

● Explaination -

Moles of HCl are -

n(HCl) = W(HCl) / M(HCl)

n(HCl) = 73/36.5

n(HCl) = 2 mol

Moles of H-atoms in HCl is -

n1 = 1 × 2

n1 = 2 mol

Moles of H2O are -

n(H2O) = W(H2O) / M(H2O)

n(H2O) = 144/18

n(H2O) = 8 mol

Moles of H-atoms in H2O is -

n1 = 2 × 8

n1 = 16 mol

Total moles of H-atoms is -

n = n1 + n2

n = 2 + 16

n = 18 mol

Therefore, 18 gram atoms hydrogen are present in dilute acid.

Thanks dear. Hope this helps you...

Answer 2

Answer:

answer : 18 gram of H

Explanation:

HCL + H2O GIVES H3O + CL

GIVEN

MASS OF HCL : 73 gm

mass of H2O : 144 gm

now

moles of HCl = m/M

73/36.5

2 mol

mole of H2O = m/M

144/18

8 mol

total mole of H2O because there is 2 atom in H

2×8

16 mole

1 mol = 1 gram atom

total atom

atom of HCl + atom of H2O

2 + 16

18 gram of H atom