Question

74. A uniform magnetic induction point B resting
horizontally from south to north having magnitude
is 1.5 Wb/m. If a 5 MeV proton moves vertically
downwards through the field, what force will
act on it (mass of proton = 1.7 x 10-27 kg and
charge on proton = 1.6 X 10-19C)
(A) 7.4 x 10-12 N (B) 5.4 x 10-12 N
(C) 3.4 x 10-12 N
(D) 1.4 x 10-12 N.
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Answer 1

Answer:

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Explanation:

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