Question

74) At room temperature, sucrose (C12H22011) has the
appearance of a white solid powder. How many oxygen
atoms are present in 17.1 grams of sucrose?​

Answer 1

Answer:

0.55 atoms

Explanation:

Mr of C12H22O11 is 12×12+22×1+11×16=342g

342g = 11 atoms of oxygen

17.1 g = ?

17.1×11 = 188.1 / 342 = .55 atoms of Oxygen

tell me if its right or not. I tried my best