74. In a mean life of a radioactive sample :-
(1) About 1/3 of substance disintegrate
(2)About 2/3 of substance disintegrate
(3) About 90% of the substance disintegrate
(4) Almost all the substance disintegrates
shambhu805128:
we know that t mean = 1/lembda. so,lembda×t=1. also,N=N0.e^-lembda t. N=N0e^-1. N=N0/e. N0-N=N0-N0/e. =N0(1-1/e). =N0{(e-1)/e}. =N0{(2.74-1)/2.74}. =N0(1.74/2.74)~N0(2/3).
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2/3 of a sustance disintegrate
pls explain
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