Question

74. The minimum flocculation power of
KCI, MgCl2, CrCl, and SnCle for a positively
charged sol are in the order of
a) KCI < MgCl2 < CrClz < SnCl.
b)KCI = MgCl2 = CrCl3 = SnCla
c) MgCl2 < KCI < CrClz < SnCIĄ
d) SnCIs < CrClz < MgCl2 <KCI​

Answer 1

Hardy-Schulze Rule :

According to this rule, greater is the valency of coagulating ion, greater its power to cause precipitation. This is known as Hardy-Schulze rule.

minimum coagulating value for ion with maximum charge
Hence 

KCl> MgCl2 > CrCl3 > SnCl4

Answer 2

Answer:

B is the answer

Explanation:

Bcz all contains same anion i.e.,Cl-