Question

√75/√18 rationalize the denominator ​

Answer 1

$= > \frac{ \sqrt{75} }{ \sqrt{18} }$

$= > \sqrt{ \frac{75}{18} }$

$= > \sqrt{ \frac{25 \times 3}{2 \times 9} }$

$= > \frac{5}{3} \times \sqrt{ \frac{3}{2} }$

$= > \frac{5}{3} \times \frac{ \sqrt{3} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} }$

$= > \frac{5 \sqrt{6} }{6}$

:-)Hope it helps u.