Question

75. A container of volume V contains 0.28 g of N2 gas.
If the same volume of an unknown gas under similar
conditions of temperature and pressure weights 0.44
g, the molecular mass of the gas is​

Answer 1

Answer:

Mg=0.44 Mn2=0.28

(Mg/Mn2)=0.44/0.28

Mg=(0.44/0.28)×28

Mg=44

Explanation:

44 is the correct answer