75. In the adjoining figure, the bisectors of Angle A and Angle B meet in a point P. If Angle C = 100°,
Angle D = 60°. Find the measure of Angle APB.
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60°+100°+angleA+angleB=360°
AngleA+angleB=200°
1by2 angleA+1by2 angleB=100°
Therefore,
AngleBAP+angleABP+angleAPB=180°
100°+angleAPB=180°
angleAPB=180°-100°
angleAPB=80°
ANSWER:80
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