Question

75 kg missile is dropped downwards from an aeroplane and has of a speed of 60 m/s at an altitude of 850 m above the ground . determine :-
1) kinetic energy possessed by the missile at 850 m .
2) total energy possessed by missile at 850 m .

answer this urgently

Answer 1

KE of the missile at 850 m height :  1/2 m v²
     = 1/2 * 75 kg * 60² (m/s)²  =  135 kJ
Potential energy = PE = m g h = 75 kg * 9.81 m/sec² * 850 m
       = 625.3875 kJ

Total energy = 760.3875 kJ        add the PE and KE.

Answer 2

Mass=75kg

Velocity=60ms^-1

Height=850m

K.E=1 BY 2*MASS*(VELOCITY)^2

=1/2*75*(60)^2

1/2*3600*75

1800*75

=135000J

TOTAL ENERGY=K.E+P.E

P.E=MGH

75*10*850

=637500J

TOTAL ENERGY = 637500+135000

=772500J