Math, asked by nitheshgurung4, 9 months ago

75 liters of kerosene oil and 25 liters of petrol have to be kept in tins of identical size such that two kinds of oil do not mixed .how many tins will be required at least ? how many oil will each tin hold?​

Answers

Answered by shreeshb8
22

Answer:

4 tins

Step-by-step explanation:

Kerosene- 75 L

Petrol- 25 L

Total Litres = 75+25= 100 L

100 ÷ 25 = 4

Answered by leishasri
5

Answer:

Step-by-step explanation:

Also to measure 680 liters of petrol the capacity in liters must also be divisor of 680. Therefore, the required maximum quantity of the container is the H.C.F of 850 L and 680 L. Hence the maximum quantity of the container = 170 L. Required number of times = (5+4) =9

we have to keep 75l of kerosene oil and 25l of petrol in seperate identical tins

since we have to use the least number of cans, the capacity of each can has to be the HCF of 75 and 25 = 25l

by using 25l cans, kerosene oil can be kept in 3 cans and petrol can be kept in 1 can. thus, 4 cans are required at least.

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