75% of a first order reaction was completed in 32min.When was 50% of the reaction completed
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Answer:For the first order reaction,
k=2.303tlog[R]0[R]
Where, [R]0 is the initial concentration of the reactant. [R] is the concentration of the reactant after time t.
k=2.30332log10025=0.0433min−1
t12=0.693k=06930.0433=16min
Explanation:
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