Chemistry, asked by gagandhananjaya333, 8 months ago

75% of the first order is completed in 30min calculate the rate constant of the reaction​

Answers

Answered by Anonymous
292

\huge\underline{\underline{\bf \orange{Question-}}}

75% of the first order is completed in 30min calculate the rate constant of the reaction.

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • a = 100%
  • a - x = 100 - 75 ➝ 25%
  • time (t) = 30 × 60 ➝ 1800sec

\large\underline{\underline{\sf To\:Find:}}

  • Rate Constant (K)

\large{\rm We \:know\:that\:for\:1^{st}\:order\: Reaction- }

\large{\boxed{\bf \blue{K=\dfrac{2.303}{t}log\dfrac{a}{a-x}} }}

\implies{\sf \dfrac{2.303}{1800}×log\dfrac{100}{25}}

\implies{\sf \dfrac{2.303}{1800}×log4}

\implies{\sf \dfrac{2.303}{1800}×2log2}

{ log2 = 0.303 }

\implies{\sf\dfrac{2.303}{1800}×2×0.303 }

\implies{\sf \dfrac{1.39}{1800}}

\implies{\bf \red{Rate\: Constant (K)=7.7×10^{-4}sec^{-1}} }

\huge\underline{\underline{\bf \orange{Answer-}}}

Rate constant of the reaction is {\bf \red{7.7×10^{-4}sec^{-1}}}.

Similar questions